a gas is contained in a thick walled balloon. when the pressure changes from 417 mm hg to 576 mm hg, the volume changes from l to 4.78 l and the temperature changes from 497 k to 386k
we can use the combined gas law equation to solve for the initial volume [tex] \frac{P1V1}{T1} = \frac{P2V2}{T2} [/tex] parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation substituting the values in the equation [tex] \frac{417 mmHg*V}{497 K} = \frac{576mmHg*4.78L}{386K} [/tex] V = 8.50 L the initial volume is 8.50 L
