pvhartley09owl4rw pvhartley09owl4rw
  • 05-04-2019
  • Mathematics
contestada

What is the length of segment EF?


EF = square root of 58 end square root

EF = three square root of 10 end square root

EF = 9

EF = 90

What is the length of segment EF EF square root of 58 end square root EF three square root of 10 end square root EF 9 EF 90 class=

Respuesta :

calculista
calculista calculista
  • 14-04-2019

Answer:

[tex]EF=3\sqrt{10}\ units[/tex]  ------> three square root of 10

Step-by-step explanation:

we know that

the formula to calculate the distance between two points is equal to

[tex]d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}[/tex]

In this problem we have

[tex]E(-1,-1)\\F(8,-4)[/tex]  

substitute the values

[tex]EF=\sqrt{(-4+1)^{2}+(8+1)^{2}}[/tex]

[tex]EF=\sqrt{(-3)^{2}+(9)^{2}}[/tex]

[tex]EF=\sqrt{90}\ units[/tex]

[tex]EF=3\sqrt{10}\ units[/tex]

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