Ri13
Ri13 Ri13
  • 02-09-2019
  • Mathematics
contestada

I would really appreciate if anyone could sold question 201 please.​

I would really appreciate if anyone could sold question 201 please class=

Respuesta :

harpazo
harpazo harpazo
  • 02-09-2019

We need to find f inverse.

f(x) = 2(x - 4)^2

Let y = f(x)

y = 2(x - 4)^2

x = 2(y - 4)^2

x/2 = (y - 4)^2

sqrt{x/2} = sqrt{(y - 4)^2}

sqrt{x/2} = y - 4

sqrt{x/2} + 4 = y

y = sqrt{x/2} + 4

Let y = f^(-1) x

f^(-1) x = sqrt{x/2} + 4

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