adipalmer adipalmer
  • 01-11-2019
  • Mathematics
contestada

Show that in a quadrilateral ABCD, AB+BC+CD+DA<2(BD+AC)

Respuesta :

Rishi2005
Rishi2005 Rishi2005
  • 01-11-2019

Step-by-step explanation:

We know that the length of the diagonals will be more than the side.

Lets suppose the quadrilateral is a rectangle, with sides 6 and 4.

The length of a diagonal is:

√(6*6)+(4*4)

√36+16

√52

7.21(rounded off to 3 sig. fig.)

So, 6+4+6+4<2(7.21+7.21)

20< 2*14.42

20<28.84, which is true.

:)

Answer Link

Otras preguntas

The number 6 is halfway between 4.5 and 7.5.Answer the missing numbers below.The number 6 is halfway between 2.8 and .......The number 6 is halfway between -12
How do you do this algebra question
How do you do this algebra question
what does the agora tell us about the culture of athens?
Explain how engineers and scientists may work together to produce a protein in the lab.
In little Marsden the population is 17 222. The men and women together total 9142 and the women and children together total 13 201. There are ...... Women There
In the library there are 200 books. 58 of them are non-fiction. What percentage of the books are non-fiction?
An oscillator makes four vibrations in one second. What is its period and frequency?
which of the following suffered most from DDT poisoning in the great lakes region
why is red onions purple