The volume 15.0 g of O₂ has at a certain temperature and pressure is 2.16 L.
Volume is the space occupied by a three-dimensional object.
By the law of dilution
M₁/V₁ = M₂/V₂
Mass 1 is 5.00
Volume 1 is 7.20 L
Mass 2 15.0 g
Volume 2 is to find
Putting the value in the equation
5.00/ 7.20 = 15.0 / V₂
V₂ = 7.20 × 15.00/ 5.00 = 21.6
Thus, the volume will be 21.6 L.
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