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04-06-2021
Mathematics

contestada

Find the value of x. Round to the nearest.

Find the value of x Round to the nearest class=

Respuesta :

04-06-2021

Answer:

Solution given:

perpendicular [P]=x

base[B]=9

hypotenuse [H]=41

Now.

By using Pythagoras law

H²=P²+B²

41²=x²+9²

x²=41²-9²

x=[tex]\sqrt{1600}=40[/tex]

x=40 is a required answer.

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