liebcon liebcon

01-02-2017
Chemistry

contestada

The ionic product of water, Kw at 298K = 1 x 10^-14.
Given that the Kw of water at 50 degrees C is 5.47 x 10^-14, calculate the pH of water at this temperature.

Please help! thanks

Respuesta :

sciencific sciencific

02-02-2017

[H+] [OH-]= Kw
[H+] [OH-]=5.47x10^-14
Log [H+]+ Log [OH-]= -14 log 5.47
PH+POH= -13.26
we need more info to solve this

Answer Link

Otras preguntas

What would be m minus 4 in an algebraic expression

A wet towel is hanging on a clothesline in the sun. What process does the towel dry by?

a rectangular field with a area of 8000m2 is enclosed by 400m of fencing. determine dimensions to nearest tenth of a metre

Payments designed to make up for war damage are known as

What is hyperbole? Please help

Maria exercises for 2 1/7 hours every Saturday. She runs for 1/3 of the time that she exercises. How much time does she spend running every Saturday?

Why did the settlers go to new mexico during manifest destiny?

You hear a thunder 3 seconds after you see lightning. How far away is the storm?

what were the main ideas of the reformation?

write a paragraph for me using these words: art critic and art historian