[tex]h^2=\text{0}.36[/tex]
to solve this, you need to isolate x,
Step 1
square root in both sides
[tex]\begin{gathered} h^2=0.36 \\ \sqrt{h^2}=\sqrt{0.36} \\ \text{the }\sqrt{\square}\text{ eliminates the square} \\ h=\pm\sqrt{0.36} \end{gathered}[/tex]
so, there are two values for h that fit this equation
[tex]\begin{gathered} +\sqrt{0.36\text{ }}=0.6 \\ \text{and} \\ -\sqrt{0.36}=-0.6 \end{gathered}[/tex]
so, the answers are A and B
