ShephardJ474480 ShephardJ474480
  • 03-11-2022
  • Physics
contestada

A flashlight bulb uses 190.1W of power when the current in the bulb is 0.64 A. What is the voltage?

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GuruR533502 GuruR533502
  • 03-11-2022

Given:

[tex]\begin{gathered} P=190.1\text{ W} \\ I=0.64\text{ A} \end{gathered}[/tex]

The power is given as,

[tex]P=VI[/tex]

Here, P is the power, V is voltage and I is the current.

Rearranging equation in order to get voltage,

[tex]V=\frac{P}{I}[/tex]

Putting all known values,

[tex]\begin{gathered} V=\frac{190.1\text{ W}}{0.64\text{ A}} \\ =297.03\text{ V} \end{gathered}[/tex]

Therefore, the voltage is 297.03 V.

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