josh1671
josh1671 josh1671
  • 03-03-2017
  • Mathematics
contestada

4a^-(6a-2) +(3) (a^-1).please solve this.the arrows that are pointing up is exponent 2.please show work

Respuesta :

morgaine816
morgaine816 morgaine816
  • 03-03-2017
I'm going to use "x" because the program lets me put in exponents.

4[tex] x^{2} [/tex]-6x+2+3[tex] x^{2} [/tex]-1
7[tex] x^{2} [/tex]-6a-1
Then factor
(7x+1)(x-1)
Set each to 0 to solve for x
x-1=0 is x=1
7x+1=0 
7x=-1
x=[tex] \frac{-1}{7} [/tex]
So your answers are x=1 and x=[tex] \frac{-1}{7} [/tex]
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