dabmcnugget6976 dabmcnugget6976
  • 02-05-2018
  • Physics
contestada

Where must an object be placed to form an image 30.0 cm from a diverging lens with a focal length of 43.0 cm?

Respuesta :

jushmk
jushmk jushmk
  • 12-05-2018
Using lens equation;

1/o + 1/i = 1/f; where o = Object distance, i = image distance (normally negative), f = focal length (normally negative)

Substituting;

1/o + 1/-30 = 1/-43 => 1/o = -1/43 + 1/30 = 0.01 => o = 1/0.01 = 99.23 cm

Therefore, the object should be place 99.23 cm from the lens.
Answer Link

Otras preguntas

In scientific notation, what is the sum of 2.3 times 10^{-3} and 5.4 times 10^{-4}?a. 2.84 times 10^{-3}b. 5.63 times 10^{-3}c. 7.7 times 10^{-7}d. 12.42 times
What value of x makes the equation true ? 4(2x-4)=16
find the circumference of a circle whose radius is 15.4cm
What value of x makes the equation true ? 4(2x-4)=16
find the circumference of a circle whose radius is 15.4cm
What value of x makes the equation true ? 4(2x-4)=16
jasmines cd collection is 3/8 jazz 1/4 rap and the rest is rock music what is the fraction of rock music
In scientific notation, what is the sum of 2.3 times 10^{-3} and 5.4 times 10^{-4}?a. 2.84 times 10^{-3}b. 5.63 times 10^{-3}c. 7.7 times 10^{-7}d. 12.42 times
jasmines cd collection is 3/8 jazz 1/4 rap and the rest is rock music what is the fraction of rock music
What value of x makes the equation true ? 4(2x-4)=16